In fig. 9.3 if ∠aob 125° then ∠cod is equal t
WebMay 16, 2024 · In figure, chords AB and CD of circle with center O, arc same. If ∠AOB = 55°, then ∠COD will be : (A) 110° (B) 75° (C) 90° (D) 55° circle class-10 1 Answer +1 vote answered May 16, 2024 by VinodeYadav (35.7k points) selected May 17, 2024 by HarshKumar Best answer Answer is (D) 55° Chord AB = Chord CD ˆAB A B ^ = ˆC D C D ^ … WebIn Figure, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° Answers (1) Answer (D) Solution Given : ∠AOB = 125° Let ∠COD = x° As we know that the sum of …
In fig. 9.3 if ∠aob 125° then ∠cod is equal t
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WebIn Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to a. 62.5°, b. 45°, c. 35°, d. 55° In Fig. 9.4, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the . . . . From a point P which is at a distance of 13 cm from the centre O of a circle of radius 5 cm, the pai . . . . Explore math program WebOct 28, 2024 · Here is your answer: The quadrilateral angle's circle meet at the point of the supplementary angles and that is at the center. ABCD will meet at a point where it won't …
WebIn Fig. 9.25, diagonals AC and BD of quadrilateral ABCD intersect at O such that OB = OD. If AB = CD, then show that: i) ar (DOC) = ar (AOB) ii) ar (DCB) = ar (ACB) iii) DA CB. Learn … WebIf two triangles have the same base and also have equal areas, then these triangles must lie between the same parallels. Let us construct DN ⊥ AC and BM ⊥ AC. i) In ∆DON and ∆BOM, ∠DNO = ∠BMO = 90° (By construction) ∠DON = ∠BOM (Vertically opposite angles are equal) OD = OB (Given) By AAS congruence rule, ΔDON ≅ ΔBOM DN = BM (By CPCT) ... (1)
WebIn figure, if ∠AOB = 125°, then ∠COD is equal to 55°. Explanation: As in the given figure ABCD is a quadrilateral circumscribing the circle and we know that, the opposite sides of a …
WebFeb 3, 2024 · In Fig.8.7, the quadrilateral ABCD circumscribes a circle with centre O. If ∠AOB =115degree, then find ∠COD. - Sarthaks eConnect Largest Online Education Community In Fig.8.7, the quadrilateral ABCD circumscribes a circle with centre O. If ∠AOB =115degree, then find ∠COD. ← Prev Question Next Question → 0 votes 18.2k views
WebClick here👆to get an answer to your question ️ 13 In the fig. if Ill m, then x is equal to ------- 1250 hot tub and spa show green bayWebIn Fig. 9.3, if AOB = 125°, then COD is equal to CBSE Circles Class 10 Exercise 9.1 Maths NCERT Exemplar In Fig. 9.3, if AOB = 125°, then COD is equal to (A) 62.5° (B) 45° … hot tub and spa shows in the alWebApr 27, 2024 · In figure, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° Solution: (D) We know that the opposite sides of a quadrilateral circumscribing a … hot tub and spa near charlestonWebIn Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to a. 62.5° b. 45° c. 35° d. 55° Solution: Given, ∠AOB = 125° We have to find the measure of angle COD. hot tub and spa show in syracuse ny 2015WebIn Fig. 9.3, if AOB = 125°, then COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° Solution: ABCD is a quadrilateral circumscribing the circle We know that, the opposite sides of a … line to create movement photographyWebIn figure, if ∠AOB = 125°, then ∠COD is equal to (a) 62.5° (b) 45° (c) 35° (d) 55° Solution: (d) We know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle. Question 3: In figure, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. hot tub and spa store near meWebIn Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to a. 62.5° b. 45° c. 35° d. 55° Solution: Given, ∠AOB = 125° We have to find the measure of angle COD. From the figure, We … hot tub and spa stores